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Topic 1 of 9 · Form 3

Functions

Domain, range, one-one and many-one mappings; composite functions fg(x) = f(g(x)); inverse functions f⁻¹ (only for one-one functions); the graphs of f and f⁻¹ are reflections in y = x.

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  1. PDFFunctions – Additional Mathematics notes (Cambridge O Level)46.1 KB

Definitions

Domain, range, one-one and many-one mappings; composite functions fg(x) = f(g(x)); inverse functions f⁻¹ (only for one-one functions); the graphs of f and f⁻¹ are reflections in y = x.

Worked example: f(x) = 2x + 3 and g(x) = x² − 1. Find fg(x), gf(2) and f⁻¹(x).

fg(x) = 2(x² − 1) + 3 = 2x² + 1

gf(2) = g(7) = 48

y = 2x + 3 → f⁻¹(x) = (x − 3)/2

Modulus functions

|f(x)| reflects parts of the graph below the x-axis. Solve |ax + b| = c by considering ax + b = c and ax + b = −c; solve |ax + b| = |cx + d| by squaring both sides.

Worked example: Solve |2x − 1| = 5.

2x − 1 = 5 → x = 3; 2x − 1 = −5 → x = −2

Graphs

Sketch y = |f(x)| for linear and quadratic f; know the shapes of cubic, exponential and logarithmic graphs.

Exam tip: State the domain and range of an inverse function – they are the range and domain of the original.

Check yourself

  1. f(x) = x² + 2, x ≥ 0. Find the range of f and f⁻¹(x).
  2. Solve |x + 3| = |2x|.
  3. Why does f(x) = x², x ∈ ℝ, not have an inverse?
Show answers
  1. Range f(x) ≥ 2; f⁻¹(x) = √(x − 2), x ≥ 2
  2. (x + 3)² = 4x² → 3x² − 6x − 9 = 0 → x = 3 or x = −1
  3. It is many-one (e.g. f(2) = f(−2)).
Next topicQuadratics, inequalities and polynomials

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