Topic 6 of 6 · Form 6
Organic chemistry: oxygen and nitrogen compounds, polymers and analysis
Alcohols: oxidation (primary → aldehyde → carboxylic acid; secondary → ketone), dehydration, esterification, reaction with sodium; the iodoform test for CH₃CH(OH)–. Phenol: acidity, reactions with bromine water and diazonium salts.
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Hydroxy compounds
Alcohols: oxidation (primary → aldehyde → carboxylic acid; secondary → ketone), dehydration, esterification, reaction with sodium; the iodoform test for CH₃CH(OH)–. Phenol: acidity, reactions with bromine water and diazonium salts.
Carbonyl compounds
Nucleophilic addition with HCN; reduction with NaBH₄; tests with 2,4-DNPH, Tollens' and Fehling's reagents.
Carboxylic acids and derivatives
Acidity and relative strengths (electron-withdrawing groups); acyl chlorides (addition–elimination with water, alcohols, amines); esters (hydrolysis); amides.
Nitrogen compounds
Amines (basicity: alkylamines > ammonia > phenylamine); diazotisation and azo dyes; amino acids (zwitterions, isoelectric point); peptides and proteins.
Polymers
Addition polymers; condensation polymers – polyesters and polyamides (nylon, Kevlar); biodegradability.
Organic synthesis and analysis
Multi-step synthetic routes; chromatography (TLC, GC); infrared spectroscopy (O–H, C=O, N–H); mass spectrometry (M⁺ peak, M+1 for carbon count, fragmentation); carbon-13 and proton NMR (chemical shift, splitting by the n + 1 rule, D₂O exchange).
Worked example: An M⁺ peak has height 30.0 and the M+1 peak 2.0. Estimate the number of carbon atoms.
n = (2.0 ÷ 30.0) × (100 ÷ 1.1) ≈ 6
Check yourself
- Why is phenylamine a weaker base than ethylamine?
- What does a triplet in proton NMR indicate?
- Which reagent reduces aldehydes to primary alcohols?
Show answers
- The nitrogen lone pair is delocalised into the benzene ring, making it less available.
- The protons have two neighbouring hydrogen atoms (n + 1 = 3).
- NaBH₄ (sodium tetrahydridoborate).
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