ZIMSEC A Level · Chemistry · Form 5, Form 6
Periodicity (Period 3)
- Atomic radius decreases across the period (increasing nuclear charge, same shielding).
- Melting point rises to silicon (giant covalent), then falls for simple molecular P₄, S₈, Cl₂ and Ar.
- Oxides change from basic (Na₂O, MgO) through amphoteric (Al₂O₃) to acidic (SiO₂, P₄O₁₀, SO₂, SO₃).
Group 2
Reactivity increases down the group. Hydroxides become more soluble and sulfates less soluble down the group; carbonates and nitrates become more thermally stable down the group (larger cations polarise the anion less).
Group 17 (halogens)
Oxidising power decreases down the group. Halide ions: reducing power increases down the group (I⁻ reduces sulfuric acid to H₂S). Tests: silver nitrate gives AgCl (white, soluble in dilute NH₃), AgBr (cream, soluble in concentrated NH₃), AgI (yellow, insoluble). Chlorine disproportionates in NaOH (bleach) and is used to treat water.
Transition elements
d-block elements forming at least one stable ion with a partly filled d sub-shell.
Properties: variable oxidation states, coloured ions (d–d transitions when ligands split the d orbitals), catalytic activity, and complex ion formation.
- Ligands donate lone pairs (dative bonds): H₂O, NH₃, Cl⁻, CN⁻, EDTA⁴⁻ (hexadentate).
- Shapes: octahedral ([Cu(H₂O)₆]²⁺), tetrahedral ([CuCl₄]²⁻), square planar (cisplatin).
- Ligand exchange changes colour: [Cu(H₂O)₆]²⁺ (blue) → [Cu(NH₃)₄(H₂O)₂]²⁺ (deep blue) with excess ammonia.
Check yourself
- Why does atomic radius decrease across Period 3?
- Describe the test for bromide ions.
- Give three characteristic properties of transition elements.
Show answers
- Nuclear charge increases while shielding stays similar, so electrons are pulled closer.
- Add dilute nitric acid then silver nitrate: cream precipitate, soluble in concentrated ammonia.
- Any three: variable oxidation states, coloured compounds, catalytic activity, form complex ions.
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