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October 18, 2026

Thermal physics and ideal gases

ZIMSEC A Level · Physics · Form 5, Form 6

Temperature and internal energy

Internal energy is the sum of the random kinetic and potential energies of the molecules. Thermodynamic temperature T (K) = θ (°C) + 273.15; absolute zero is 0 K.

Specific heat capacity and latent heat

Q = mcΔθ; Q = mL (latent heat of fusion or vaporisation – energy breaks intermolecular bonds without changing temperature).

Worked example: Find the energy needed to turn 0.20 kg of ice at 0 °C into water at 20 °C (Lf = 3.34 × 10⁵ J kg⁻¹, c = 4 200 J kg⁻¹ K⁻¹).

Melting: 0.20 × 3.34 × 10⁵ = 66 800 J; heating: 0.20 × 4 200 × 20 = 16 800 J

Total = 83 600 J ≈ 8.4 × 10⁴ J

Ideal gases

  • pV = nRT = NkT (R = 8.31 J mol⁻¹ K⁻¹, k = 1.38 × 10⁻²³ J K⁻¹).
  • Kinetic theory: pV = ⅓Nm⟨c²⟩; mean kinetic energy of a molecule = (3/2)kT.

Worked example: A gas occupies 0.024 m³ at 100 kPa and 300 K. How many moles are there?

n = pV/RT = (1.0 × 10⁵ × 0.024) ÷ (8.31 × 300) = 0.96 mol

First law of thermodynamics

ΔU = q + W (heat supplied to the system plus work done on the system).

Exam tip: Always use kelvin in gas law calculations – using °C gives wrong answers.

Check yourself

  1. Convert 27 °C to kelvin.
  2. A gas at 300 K is heated at constant volume until its pressure doubles. Find the new temperature.
  3. What happens to the mean kinetic energy of gas molecules if the temperature in kelvin doubles?
Show answers
  1. 300 K (300.15 K)
  2. 600 K
  3. It doubles.

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